How do you simplify #-4sqrt(7/8)#?

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Answer 1 · 2018-04-02T18:44:06

The expression simplifies to #-sqrt14#.

#color(white)=-4sqrt(7/8)#

#=-4*sqrt(7/8)#

#=-4*sqrt7/sqrt8#

#=-4*sqrt7/sqrt(4*2)#

#=-4*sqrt7/(sqrt4*sqrt2)#

#=-4*sqrt7/(2*sqrt2)#

#=-4*sqrt7/(2*sqrt2)color(red)(*sqrt2/sqrt2)#

#=-4*(sqrt7*sqrt2)/(2*sqrt2*sqrt2)#

#=-4*(sqrt7*sqrt2)/(2*(sqrt2)^2)#

#=-4*(sqrt7*sqrt2)/(2*2)#

#=-4*(sqrt7*sqrt2)/(4)#

#=-color(red)cancelcolor(black)4*(sqrt7*sqrt2)/color(red)cancelcolor(black)(4)#

#=-sqrt7*sqrt2#

#=-sqrt14#

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