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How do you simplify $- 4 \sqrt{28 x} \cdot \sqrt{7 x^{3}}$ $-4sqrt(28x)*sqrt(7x^3)$ ?

1 Answer

Aug 14, 2016

$- 56 x^{2}$ $-56x^2$

Explanation:

When multiplying two square roots, we can multiply them into one root.
Write the numbers as the product of prime factors.

$- 4 \sqrt{28 x} \cdot \sqrt{7 x^{3}} = - 4 \sqrt{2 \times 2 \times 7 \times 7 \times x^{4}}$ $-4sqrt(28x)*sqrt(7x^3) = -4sqrt(2xx2xx7xx7xx x^4)$

= $- 4 \times 2 \times 7 \times x^{2} = - 56 x^{2}$ $-4 xx2xx7xxx^2 = -56x^2$

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