How do you simplify 4- sqrt( r+6) = -sqrt( r-2)?

1 Answer
Cesareo R.
May 14, 2016

r = 3

Explanation:

grouping 4= sqrt[r+6]-sqrt[r-2] and squaring both sides of the equation,
16 = 4+2r+2sqrt((r+6)(r-2))
Simplifying and grouping radicals to the right
6-r=sqrt((r+6)(r-2))
Squaring again both sides
(6-r)²=(r+6)(r-2)
After simplifications we get
r = 3

Related questions
See all questions in Radical Equations
Impact of this question
1381 views around the world
You can reuse this answer
Creative Commons License