How do you simplify 4- sqrt( r+6) = -sqrt( r-2)4−√r+6=−√r−2?

1 Answer
Cesareo R.
May 14, 2016

r = 3r=3

Explanation:

grouping 4= sqrt[r+6]-sqrt[r-2] 4=√r+6−√r−2 and squaring both sides of the equation,
16 = 4+2r+2sqrt((r+6)(r-2))16=4+2r+2√(r+6)(r−2)
Simplifying and grouping radicals to the right
6-r=sqrt((r+6)(r-2))6−r=√(r+6)(r−2)
Squaring again both sides
(6-r)²=(r+6)(r-2)
After simplifications we get
r = 3

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