How do you simplify #4(2sqrt2 + 3sqrt2)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer EZ as pi Jun 17, 2016 #=20sqrt2# Explanation: It will help to realise that #sqrt2# can be used as like terms. In the same way that #2 xx 7 + 3 xx 7# can be written as #5 xx 7#, #2sqrt2 + 3sqrt2= 5sqrt2# #4(2sqrt2 + 3sqrt2) = 4(5sqrt2)# #=20sqrt2# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 888 views around the world You can reuse this answer Creative Commons License