How do you simplify #(4 / 2) + 4(5 - 2)^2#?

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How do you simplify #(4 / 2) + 4(5 - 2)^2#?

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Answer 1 · 2015-09-22T23:44:11

I found: #38#

Explanation:

I would first deal with the operations inside the parenthesis and get:
#(cancel(4)^2/cancel(2))+4(3)^2=2+4(3)^2=# then solve the square:
#=2+4*9=# multiply:
#=2+36=# and finally add:
#=38#

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How do you simplify #(4 / 2) + 4(5 - 2)^2#?

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