How do you simplify #((-3x^-6y^-1z^-2)/(6x^-2yz^-5))^-2#?

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Answer 1 · 2017-04-30T13:36:31

See below.

We know that when there is a negative we flip the expression (i.e, #x^-1=1/x#).

Let's do that for this expression first.

#((-3x^-6y^-1z^-2)/(6x^-2yz^-5))^-2#

#((-3x^2z^5)/(6x^6y^2z^2))^-2#

Now we simplify like terms.

#((-z^3)/(x^4y^2))^-2#

Since the expression is to the #-2#, we again flip everything.

#((x^4y^2)/(-z^3))^2#

Now we square each term.

#(x^8y^4)/(z^6)#