How do you simplify (3x^2+6y)/(3x^2+9x)3x2+6y3x2+9x?

1 Answer
Pythagoras
Sep 25, 2015

(x^2 + 2y)/(x*(x + 3)x2+2yx⋅(x+3)

Explanation:

(3x^2 +6y)/(3x^2 +9x)3x2+6y3x2+9x

Factor out 3 from numerator, and 3x from the denominator:
=(3*x^2 + (3*2)y)/(3x*x + 3*3x)=3⋅x2+(3⋅2)y3x⋅x+3⋅3x
=(3*(x^2 + 2y))/(3x*(x + 3))=3⋅(x2+2y)3x⋅(x+3)

Then cancel out the 3 from the numerator and the denominator:
=(cancel 3*(x^2 + 2y))/(cancel 3 x*(x + 3))

So you have:
=(x^2 + 2y)/(x*(x + 3)

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