How do you simplify $\frac{3 w^{2} - 12}{w^{2} + 5 w + 6}$ $(3w^2-12)/(w^2+5w+6)$ ?

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Answer 1 · 2016-09-20T02:36:26

We must factor both the numerator and the denominator.

$= \frac{3 (w^{2} - 4)}{(w + 3) (w + 2)}$ $=(3(w^2 - 4))/((w + 3)(w + 2))$

$= \frac{3 (w + 2) (w - 2)}{(w + 3) (w + 2)}$ $= (3(w + 2)(w - 2))/((w + 3)(w + 2))$

$= \frac{3 (w - 2)}{w + 3}$ $=(3(w - 2))/(w +3)$

Finally, let's note the restrictions on the variable. We cannot have the denominator equal 0, so $w \neq 3 and - 2$ $w !=3 and -2$ .

Hopefully this helps!

How do you simplify 3w2−12w2+5w+6(3w^2-12)/(w^2+5w+6)?