How do you simplify #(3w^2-12)/(w^2+5w+6)#?

1 Answer
Noah G
Sep 20, 2016

We must factor both the numerator and the denominator.

#=(3(w^2 - 4))/((w + 3)(w + 2))#

#= (3(w + 2)(w - 2))/((w + 3)(w + 2))#

#=(3(w - 2))/(w +3)#

Finally, let's note the restrictions on the variable. We cannot have the denominator equal 0, so #w !=3 and -2#.

Hopefully this helps!

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