How do you simplify #3sqrt8#? Algebra Radicals and Geometry Connections Simplification of Radical Expressions 1 Answer McKenzie · NJ · Serena D. Mar 22, 2018 #6sqrt2# Explanation: The square root of #8# is like the square root of #4# times #2#. #3sqrt(8) = 3sqrt(4xx2)# The square root of #4# is #2# so you multiply #3# by #2# and leave the other #2# in the square root. #3sqrt(4xx2) = 3xx2sqrt(2)# You are then left with #6# times the square root of #2#. #6sqrt2# Answer link Related questions How do you simplify radical expressions? How do you simplify radical expressions with fractions? How do you simplify radical expressions with variables? What are radical expressions? How do you simplify #root{3}{-125}#? How do you write # ""^4sqrt(zw)# as a rational exponent? How do you simplify # ""^5sqrt(96)# How do you write # ""^9sqrt(y^3)# as a rational exponent? How do you simplify #sqrt(75a^12b^3c^5)#? How do you simplify #sqrt(50)-sqrt(2)#? See all questions in Simplification of Radical Expressions Impact of this question 3515 views around the world You can reuse this answer Creative Commons License