How do you simplify #(3sqrt R )/ (3 sqrtx)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Alan P. Sep 4, 2015 #(3sqrt(R))/(3sqrt(x)) = sqrt(R/x)# Explanation: #(color(red)(3sqrt(R)))/(color(blue)(3sqrt(x)))# #= color(red)(3 * sqrt(R)) * color(blue)(1/3 * 1/sqrt(x))# #= cancel(color(red)(3))*1/cancel(color(blue)(3))*color(red)(sqrt(R))/color(blue)(sqrt(x))# #= sqrt(color(red)(R)/color(blue)(x)# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1017 views around the world You can reuse this answer Creative Commons License