How do you simplify #(3² + 3)²#? Algebra Expressions, Equations, and Functions PEMDAS 1 Answer Shwetank Mauria May 17, 2016 #(3^2+3)^2=144# Explanation: #(3^2+3)^2=(3^2+3xx1)^2# = #(3xx(3+1))^2# = #(3xx4)^2=12^2=144# Answer link Related questions What is PEMDAS? How do you use PEMDAS? How do you use order of operations to simplify #3(7-2)-8#? What are common mistakes students make with PEMDAS? How do you evaluate the expression #5[8+(3-1)]-2#? How do you simplify the expression #4(30-(3+1)^2)#? How do you evaluate the expression #x^4+x# if x=2? Is it okay to add first before subtracting in #4-6+3#? How do you simplify #(-3)^2+12*5#? How do you simplify #(4-2)^3-4*8+21div3#? See all questions in PEMDAS Impact of this question 4932 views around the world You can reuse this answer Creative Commons License