How do you simplify $(3+2sqrt5)^2$ ?

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Answer 1 · 2016-09-09T18:59:58

$12sqrt5 +29$

The square of a binomial gives a trinomial.
Each term in the first bracket must multiply by each term in the second bracket.

$(3+2sqrt5)(3+2sqrt5)$

= $9+6sqrt5 + 6sqrt5 +4 xx5$

= $12sqrt5 +29$

Recall: $sqrtx xx sqrtx = sqrt(x^2) = (sqrtx)^2 = x$

How do you simplify (3+2sqrt5)^2(3+2sqrt5)^2?