How do you simplify #( 3 - 2sqrt2 )^2#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Alan P. Jun 5, 2015 From the general form: #color(white)("XXXX")##(a-b)^2 = a^2 -2ab +b^2# We can write #color(white)("XXXX")##(3-2sqrt(2))^2 = 9 -12sqrt(2) +8# #color(white)("XXXX")##color(white)("XXXXXXX")##=17-12sqrt(2)# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1277 views around the world You can reuse this answer Creative Commons License