How do you simplify −3+2i2−5i? Precalculus Complex Zeros Complex Conjugate Zeros 1 Answer Shwetank Mauria Jun 30, 2016 −3+2i2−5i=−1629−1129i Explanation: To simplify −3+2i2−5i, we need to multiply numerator and denominator by complex conjugate of the denominator i.e. here 2+5i. Hence, −3+2i2−5i=(−3+2i)(2+5i)(2−5i)(2+5i) = −6−15i+4i+10i24−25i2 = −6−15i+4i−104+25 = −16−11i29=−1629−1129i Answer link Related questions What is a complex conjugate? How do I find a complex conjugate? What is the conjugate zeros theorem? How do I use the conjugate zeros theorem? What is the conjugate pair theorem? How do I find the complex conjugate of 10+6i? How do I find the complex conjugate of 14+12i? What is the complex conjugate for the number 7−3i? What is the complex conjugate of 3i+4? What is the complex conjugate of a−bi? See all questions in Complex Conjugate Zeros Impact of this question 6545 views around the world You can reuse this answer Creative Commons License