How do you simplify (-3 + 2i) / (2 - 5i)−3+2i2−5i?

1 Answer
Shwetank Mauria
Jun 30, 2016

(-3+2i)/(2-5i)=-16/29-11/29i−3+2i2−5i=−1629−1129i

Explanation:

To simplify (-3+2i)/(2-5i)−3+2i2−5i, we need to multiply numerator and denominator by complex conjugate of the denominator i.e. here 2+5i2+5i.

Hence, (-3+2i)/(2-5i)=((-3+2i)(2+5i))/((2-5i)(2+5i))−3+2i2−5i=(−3+2i)(2+5i)(2−5i)(2+5i)

= (-6-15i+4i+10i^2)/(4-25i^2)−6−15i+4i+10i24−25i2

= (-6-15i+4i-10)/(4+25)−6−15i+4i−104+25

= (-16-11i)/29=-16/29-11/29i −16−11i29=−1629−1129i

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