How do you simplify $3^{2} + (1 + 4) - 2$ $3^2+(1+4)-2$ using order of operations?

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How do you simplify $3^{2} + (1 + 4) - 2$ $3^2+(1+4)-2$ using order of operations?

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Answer 1 · 2018-06-16T17:49:16

$12$ $12$

Explanation:

$using the order of operations PEMDAS$ $"using the order of operations PEMDAS"$

$[P-parenthesis (brackets),E-exponents (powers),$ $["P-parenthesis (brackets),E-exponents (powers),"$
$M-multiplication, D-division, A-addition, S-subtraction]$ $"M-multiplication, D-division, A-addition, S-subtraction"]$

$3^{2} + 5 - 2 \leftarrow parenthesis$ $3^2+5-2larrcolor(red)"parenthesis"$

$= 9 + 5 - 2 \leftarrow exponents$ $=9+5-2larrcolor(red)"exponents"$

$for addition/subtraction evaluate from left to right$ $"for addition/subtraction evaluate from left to right"$

$= 14 - 2$ $=14-2$

$= 12$ $=12$

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How do you simplify $3^{2} + (1 + 4) - 2$ $3^2+(1+4)-2$ using order of operations?

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