How do you simplify #(2x^3z^2)^3/(x^3y^4z^2*x^-4z^3)# and write it using only positive exponents?

1 Answer
sankarankalyanam
Jul 2, 2018

#color(brown)(=> (8 x^10 z) / y^4#

Explanation:

#(2x^3z^2)^3 / (x^3y^4z^2 * x^-4z^3)#

![http://quantbasics.blogspot.com/2010/04/http://indices-and-surds.html](https://useruploads.socratic.org/FO4iXhh3QEm2Cf0TAVE9_Laws%20of%20Indices.jpg)

using Laws of Indices,

#=> (2^3 x^(3 * 3) z^(2 *3)) / (x^(3-4) y^4 z^(2 + 3))#

#=> (8 x^9 z^6) / (x^-1 y^4 z^5)#

#=> (8 x^(9 + 1) z^(6-5)) / y^4#

#color(brown)(=> (8 x^10 z) / y^4#

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