How do you simplify $(2 \sqrt{3} + 3 \sqrt{2}) (3 \sqrt{3} - \sqrt{2})$ $(2sqrt3+3sqrt2)(3sqrt3 -sqrt2)$ ?

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How do you simplify $(2 \sqrt{3} + 3 \sqrt{2}) (3 \sqrt{3} - \sqrt{2})$ $(2sqrt3+3sqrt2)(3sqrt3 -sqrt2)$ ?

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Answer 1 · 2016-07-06T09:30:46

$12 + 7 \sqrt{6}$ $12+7sqrt6$

Explanation:

$(2 \sqrt{3} + 3 \sqrt{2}) (3 \sqrt{3} - \sqrt{2})$ $(2sqrt3+3sqrt2)(3sqrt3 -sqrt2)$

Each term in the first bracket has to be multiplied by each term in the other bracket.

Note: $\sqrt{3} \times \sqrt{3} = {\sqrt{3}}^{2} = 3$ $sqrt3xxsqrt3 = sqrt3^2 = 3$

$(6 \sqrt{3} \times \sqrt{3}) - (2 \sqrt{3} \times \sqrt{2}) + (9 \sqrt{2} \sqrt{3}) - (3 \sqrt{2} \times \sqrt{2})$ $(6sqrt3xxsqrt3) - (2sqrt3xxsqrt2) + (9sqrt2sqrt3) -(3sqrt2xxsqrt2)$

$6 \times 3 + (- 2 \sqrt{6} + 9 \sqrt{6}) - 3 \times 2$ $6xx3 + (- 2sqrt6 + 9sqrt6) -3 xx2$

$18 + 7 \sqrt{6} - 6$ $18+7sqrt6 -6$

$12 + 7 \sqrt{6}$ $12+7sqrt6$

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How do you simplify $(2 \sqrt{3} + 3 \sqrt{2}) (3 \sqrt{3} - \sqrt{2})$ $(2sqrt3+3sqrt2)(3sqrt3 -sqrt2)$ ?

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How do you simplify (2√3+3√2)(3√3−√2)(2sqrt3+3sqrt2)(3sqrt3 -sqrt2)?

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How do you simplify $(2 \sqrt{3} + 3 \sqrt{2}) (3 \sqrt{3} - \sqrt{2})$ $(2sqrt3+3sqrt2)(3sqrt3 -sqrt2)$ ?