How do you simplify #(21!)/(14!)#?

1 Answer
MeneerNask
Oct 13, 2016

By cancelling common factors.

Explanation:

By definition:
#21! =21xx20xx19xx....xx15xx14xx13...xx2xx1#
#14! =14xx13xx12xx....xx2xx1#

So we can cancel all factors from #14# downward.
Which leaves:

#=21xx20xx19xx18xx17xx16xx15#

Related questions
See all questions in Factorial Identities
Impact of this question
2114 views around the world
You can reuse this answer
Creative Commons License