How do you simplify #(2^4)^2 /( 2 •2^0)#?

2 Answers
冠廷 李.
Jun 17, 2016

#2^7#

Explanation:

use exponent rule
#(2^4)^2=2^8#
#2^0=1#
#2^a/2^b=2^(a-b)#
clearly
#2^8/2=2^7#

EZ as pi
Jun 17, 2016

It is possible to calculate this without finding the actual numbers , but by using laws of indices.

In the numerator, multiply the indices.
In the denominator, anything to a power of 0 is equal to 1. (except 0)

#2^8/(2 xx 1)#

Subtract the indices of like bases..(All 2)

#2^(8-1) = 2^7 = 128#
#2^7 = 128#

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