How do you simplify $(\frac{2}{15}) (\frac{25}{49}) (- \frac{63}{72})$ $(2/15)(25/49)(-63/72)$ ?

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How do you simplify $(\frac{2}{15}) (\frac{25}{49}) (- \frac{63}{72})$ $(2/15)(25/49)(-63/72)$ ?

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Answer 1 · 2018-02-05T14:35:46

$- \frac{5}{84}$ $-5/84$

Explanation:

$note that - \frac{63}{72} can be simplified$ $"note that "-63/72" can be simplified"$

$by cancelling numerator/denominator by 9$ $"by "color(blue)"cancelling "" numerator/denominator by 9"$

$rArr-63/72=-cancel(63)^7/cancel(72)^8=-7/8$

$"thus the calculation becomes"$

$2/15xx25/49xx-7/8$

$"simplify further by cancelling 2/8, 15/25 and 7/49"$

$cancel(2)^1/cancel(15)^3xxcancel(25)^5/cancel(49)^7xx-cancel(7)^1/cancel(8)^4$

$"multiply the remaining values on the "$
$"numerator/denominator"$

$=(1xx5xx-1)/(3xx7xx4)=-5/84$

Answer 2 · 2018-02-05T14:43:39

$-5/84$

Explanation:

Start by cancelling with any common factors in the numerators and denominators.

$2/15 xx25/49 xx-63/72$

$div 5 (15 and 25)and div 7 (49 and 63)$

$=-2/cancel15^3 xxcancel25^5/cancel49^7 xxcancel63^9/72$

$=-cancel2/3 xx5/7 xxcancel9/(cancel72^(cancel8^4))$

$div 9 (9 and 72) and div 2 (2 and 8)$

$=5/(3xx7xx4)$

$= -5/(84)$

There are different ways of cancelling. The order is not important.

This is easier than multiplying all the tops together and all the bottoms together and then trying to simplify.

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How do you simplify $(\frac{2}{15}) (\frac{25}{49}) (- \frac{63}{72})$ $(2/15)(25/49)(-63/72)$ ?

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How do you simplify $(\frac{2}{15}) (\frac{25}{49}) (- \frac{63}{72})$ $(2/15)(25/49)(-63/72)$ ?