How do you simplify $(-16a^2bc^4)/(8ab^2c^4)$ ?

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How do you simplify $(-16a^2bc^4)/(8ab^2c^4)$ ?

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Answer 1 · 2018-04-19T21:43:07

#(2a)/b

Explanation:

You have to subtract the exponent of each variable/number in denominator from the exponent in the numerator...
$-(2^4*a^2*b^1*c^4)/(2^3*a^1*b^2*c^4)$
- $2^(4-3)*a^(2-1)*b^(1-2)*c^(4-4)$
- $2^1*a^1*b^-1*c^0$ Simplify
$(2a)/b$

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How do you simplify $(-16a^2bc^4)/(8ab^2c^4)$ ?

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How do you simplify (-16a^2bc^4)/(8ab^2c^4)(-16a^2bc^4)/(8ab^2c^4)?

1 Answer

Explanation:

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How do you simplify $(-16a^2bc^4)/(8ab^2c^4)$ ?