How do you simplify #(-16a^2bc^4)/(8ab^2c^4)#?

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How do you simplify #(-16a^2bc^4)/(8ab^2c^4)#?

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Answer 1 · 2018-04-19T21:43:07

#(2a)/b

Explanation:

You have to subtract the exponent of each variable/number in denominator from the exponent in the numerator...
#-(2^4*a^2*b^1*c^4)/(2^3*a^1*b^2*c^4)#
-#2^(4-3)*a^(2-1)*b^(1-2)*c^(4-4) #
-#2^1*a^1*b^-1*c^0# Simplify
#(2a)/b#

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How do you simplify #(-16a^2bc^4)/(8ab^2c^4)#?

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