How do you rewrite the equation #2y+3x=4# in slope intercept form?

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Answer 1 · 2018-06-19T23:50:18

#y = -3/2x - 2#

First, write the equation

#y = mx+b#

and look at the equation you are given. From there, solve the equation to get #y# by itself you will end up with

#2y = 4-3x#

Then, divide both sides by two to get the unit rate

#y = 2-(3x)/2#

After, switch the two values on the right side to get

#y = -3/2x -2#

I hope this helps!

Answer 2 · 2018-06-19T23:53:48

#y=-3/2x+2#

Given:

#2y+3x=4#

Rewrite in the standard form for a linear equation: #Ax+By=C#

#3x+2y=4#

The slope-intercept form for a linear equation is #y=mx+b#,

where:

#m# is the slope and #b# is the y-intercept.

To convert the standard form to slope-intercept form, solve for #y#.

#3x+2y=4#

Subtract #3x# from both sides.

#2y=-3x+4#

Divide both sides by #2#.

#y=-3/2x+4/2#

Simplify.

#y=-3/2x+2#

graph{(3x+2y-4)(y+3/2x-2)=0 [-9.96, 10.04, -2.76, 7.24]}