How do you rewrite the equation 2x + 3y = 6 in slope-intercept form?

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Answer 1 · 2016-05-06T16:43:47

#y = -2/3x+2#

Isolate #y# on the left hand side of the equation as follows:

Given:

#2x+3y=6#

Subtract #2x# from both sides to get:

#3y = -2x+6#

Divide both sides by #3# to get:

#y = -2/3x+2#

This is in slope intercept form:

#y = mx+c#

with slope #m=-2/3# and (#y#) intercept #c=2#.