How do you plot (-3, 2 ), (-2, 1), (1, -2)?

1 Answer
Aug 1, 2015

These three points are colinear, lying on the line:

y=-x-1y=x1

Explanation:

You can calculate the slope mm of a line through any pair of points (x_1, y_1)(x1,y1) and (x_2, y_2)(x2,y2) using the formula:

m = (Delta y)/(Delta x) = (y_2 - y_1) / (x_2 - x_1)

So the slope of a line through (-3, 2) and (-2, 1) is:

(1 - 2)/(-2 - (-3)) = -1/1 = -1

The slope of a line through (-2, 1) and (1, -2) is:

(-2 - 1) / (1 - (-2)) = (-3)/3 = -1

So these three points are colinear with slope -1.

Then since the line passes through (1, -2), we know:

y+2 = -1(x-1) = -x+1

Subtract 2 from both sides to get:

y = -x-1

graph{(y+x+1)((x+3)^2+(y-2)^2-0.02)((x+2)^2+(y-1)^2-0.02)((x-1)^2+(y+2)^2-0.02) = 0 [-10.96, 9.04, -4.96, 5.04]}