How do you normalize $(i+k)$ ?

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Answer 1 · 2016-01-03T21:25:39

Divide by the scalar $abs(i+k) = sqrt(2)$ to get:

$sqrt(2)/2 i + sqrt(2)/2 k$

$abs(i+k) = sqrt(1^2+1^2) = sqrt(2)$

So multiplying by $1/sqrt(2) = sqrt(2)/2$ we find:

$abs(sqrt(2)/2 i + sqrt(2)/2 k) = sqrt((sqrt(2)/2)^2 + (sqrt(2)/2)^2)$

$= sqrt(1/2+1/2) = sqrt(1) = 1$

How do you normalize (i+k)(i+k)?