How do you normalize $(i + 7 j + 4 k)$ $( i + 7 j + 4 k )$ ?

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How do you normalize $(i + 7 j + 4 k)$ $( i + 7 j + 4 k )$ ?

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Answer 1 · 2016-03-08T16:25:51

The normalized vector is the unit vector form to you vector, thus:
$\to u = \frac{1}{\sqrt{66}} (i + 7 j + 4 k)$ $vec(u) = 1/sqrt(66) ( i + 7j +4k)$

Explanation:

Normalization implies finding the unit vector expression to you vector quantity. So given you vector:
$\to v = i + 7 j + 4 k$ $vec(v) = i + 7j +4k$ the unit vector is:
$\to u = \frac{1}{∣ ∣ \to v ∣ ∣} \to v; ∣ ∣ \to v ∣ ∣ = \sqrt{1 + 49 + 16} = \sqrt{66}$ $vec(u) = 1/|vec(v)| vec(v); |vec(v)| = sqrt(1 + 49 + 16) = sqrt(66)$
$\to u = \frac{1}{\sqrt{66}} (i + 7 j + 4 k)$ $vec(u) = 1/sqrt(66) ( i + 7j +4k)$
Your vector can be written as:
$\to v = ∣ ∣ \to v ∣ ∣ \to u = \sqrt{66} \to u$ $vec(v) = |vec(v)| vec(u) = sqrt(66) vec(u)$

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How do you normalize $(i + 7 j + 4 k)$ $( i + 7 j + 4 k )$ ?

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How do you normalize ( i + 7 j + 4 k )(i+7j+4k)( i + 7 j + 4 k )?

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How do you normalize $(i + 7 j + 4 k)$ $( i + 7 j + 4 k )$ ?