How do you normalize $(i -2j + 3k)$ ?

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Answer 1 · 2017-12-28T16:16:12

$1/sqrt14(hati-2hatj+3hatk)$

to normalize a vector means to change it to a unit vector, that is ensure that its magnitude is $=1$

$hatveca=(veca)/|veca|$

we ahve

$veca=hati-2hatj+3hatk$

$|a|14$

$=sqrt(1^2+2^2+3^2)=sqrt14$

$hatveca=1/sqrt14(hati-2hatj+3hatk)$

How do you normalize (i -2j + 3k) (i -2j + 3k) ?