How do you normalize $(i+2j+2k)$ ?

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Answer 1 · 2018-07-26T14:31:10

The answer is $=<1/3,2/3,2/3>$

To normalize a vector $veca$ , calculate

$hata=veca/(||veca||)$

Here,

$veca = <1,2,2>$

The norm is

$||veca ||= ||<1,2,2>|| = sqrt(1^2+2^2+2^2)$

$=sqrt(1+4+4)$

$=sqrt9$

$=3$

Therefore,

$hata=1/3 <1,2,2> = <1/3,2/3,2/3>$

How do you normalize (i+2j+2k)(i+2j+2k)?