How do you normalize #( i - 2 j + 3 k )#?

1 Answer
Cosmic Defect
Feb 15, 2016

Please check the explanation below.

Explanation:

A vector is normalised by dividing that with its magnitude. Suppose if #\vec{A_{}} = A_x\hat{i}+A_y\hat{j}+A_z\hat{k}# is the vector, its magnitude #A = |\vec{A_{}}| = \sqrt{A_x^2+A_y^2+A_z^2}#.

So the normalised vector is #\hat{A} = \vec{A_{}}/A=A_x/A\hat{i}+A_y/A\hat{j}+A_z/A\hat{k}#.

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