How do you normalize (8i + 12j + 14k) ?

1 Answer
ali ergin
Feb 13, 2016

vec u=8/sqrt 404*i+12/sqrt 404*j+14/sqrt 404*k

Explanation:

vec v=(8i+12j+14k)
vec u=vec v/| vec v|
vec u=(8i+12j+14k)/sqrt(8^2+12^2+14^2)
vec u=(8i+12j+14k)/sqrt (64+144+196)
vec u=(8i+12j+14k)/sqrt 404
vec u=8/sqrt 404*i+12/sqrt 404*j+14/sqrt 404*k

Related questions
See all questions in Vector Operations
Impact of this question
1666 views around the world
You can reuse this answer
Creative Commons License