How do you normalize # (8i + 12j + 14k) #?

1 Answer
ali ergin
Feb 13, 2016

#vec u=8/sqrt 404*i+12/sqrt 404*j+14/sqrt 404*k#

Explanation:

#vec v=(8i+12j+14k)#
#vec u=vec v/| vec v|#
#vec u=(8i+12j+14k)/sqrt(8^2+12^2+14^2)#
#vec u=(8i+12j+14k)/sqrt (64+144+196)#
#vec u=(8i+12j+14k)/sqrt 404#
#vec u=8/sqrt 404*i+12/sqrt 404*j+14/sqrt 404*k#

Related questions
See all questions in Vector Operations
Impact of this question
1470 views around the world
You can reuse this answer
Creative Commons License