How do you normalize (5i- 3j + 12k) ?

1 Answer
David G.
Feb 20, 2016

Normalizing a vector creates a 'unit vector' 1 unit in length in the same direction as the original vector. In this case the normalized vector is (5/sqrt178i-3/sqrt178j+12/sqrt178k) or (5/13.3i-3/13.3j+12/13.3k)

Explanation:

Normalizing a vector means dividing each of the elements by the length of the vector.

The length of this vector is l=sqrt(5^2+(-3)^2+12^2)=sqrt178~~13.3.

The normalized vector can be represented as (5/sqrt178i-3/sqrt178j+12/sqrt178k) or (5/13.3i-3/13.3j+12/13.3k).

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