How do you normalize $(3i – 4j + 4k)$ ?

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Answer 1 · 2017-07-01T06:32:03

The answer is $=3/sqrt41i-4/sqrt41j+4/sqrt41k$

Let $vecv=<3,-4,4>$

The magnitude of $vecv$ is

$||vecv||=||<3,-4,4>||=sqrt(3^2+(-4)^2+4^2)=sqrt(9+16+16)=sqrt41$

Therefore, the normalized vector is

$hatv=vecv/(||vecv||)=1/sqrt41*<3,-4,4>$

How do you normalize (3i – 4j + 4k) (3i – 4j + 4k) ?