How do you normalize (- 3 i + 12j -5k)?
1 Answer
Mar 5, 2017
Explanation:
In normalizing the vector we are finding a unit vector (magnitude/length of one) in the same direction as the given vector. This can be accomplished by dividing the given vector by its magnitude.
u=v/(|v|)
Given
|v|=sqrt((v_x)^2+(v_y)^2+(v_z)^2)
|v|=sqrt((-3)^2+(12)^2+(-5)^2)
|v|=sqrt(9+144+25)
|v|=sqrt(178)
We now have:
u=(<-3,12,-5>)/sqrt(178)
Hope that helps!
