How do you normalize #<3, -6, 2>#?
1 Answer
Jan 23, 2017
Explanation:
In normalizing the vector we are finding a unit vector (magnitude/length of one) in the same direction as the given vector. This can be accomplished by dividing the given vector by its magnitude.
#u=v/(|v|)#
Given
#|v|=sqrt((v_x)^2+(v_y)^2+(v_z)^2)#
#|v|=sqrt((3)^2+(-6)^2+(2)^2)#
#|v|=sqrt(9+36+4)#
#|v|=sqrt(49)#
#|v|=7#
We now have:
#u=(<3,-6,2>)/7#
Hope that helps!
