How do you normalize <3, -6, 2>?
1 Answer
Jan 23, 2017
Explanation:
In normalizing the vector we are finding a unit vector (magnitude/length of one) in the same direction as the given vector. This can be accomplished by dividing the given vector by its magnitude.
u=v/(|v|)
Given
|v|=sqrt((v_x)^2+(v_y)^2+(v_z)^2)
|v|=sqrt((3)^2+(-6)^2+(2)^2)
|v|=sqrt(9+36+4)
|v|=sqrt(49)
|v|=7
We now have:
u=(<3,-6,2>)/7
Hope that helps!
