How do you normalize (-2i- 3j + 2k) ?
1 Answer
Mar 5, 2017
Explanation:
In normalizing the vector we are finding a unit vector (magnitude/length of one) in the same direction as the given vector. This can be accomplished by dividing the given vector by its magnitude.
u=v/(|v|)
Given
|v|=sqrt((v_x)^2+(v_y)^2+(v_z)^2)
|v|=sqrt((-2)^2+(-3)^2+(2)^2)
|v|=sqrt(4+9+4)
|v|=sqrt(17)
We now have:
u=(<-2,-3,2>)/sqrt(17)
Hope that helps!
