How do you normalize <2,0,-1>?
1 Answer
Sep 9, 2017
Explanation:
To normalize a vector is to find unit vector (vector with magnitude/length of one) in the same direction as the given vector. This can be accomplished by dividing the given vector by its magnitude.
#hatu=vecv/(|vecv|)#
Given
#abs(vecv)=sqrt((v_x)^2+(v_y)^2+(v_z)^2)#
#=>=sqrt((2)^2+(0)^2+(-1)^2)#
#=>=sqrt(4+0+1)#
#=>=sqrt(5)#
We now have:
#hatu=(<2,0,-1>)/sqrt(5)#
We can also rationalize the denominator on the
#=>hatu=<(2sqrt(5))/5,0,(-sqrt(5))/5>#
Hope that helps!
