How do you normalize <0, 4, 4>?

1 Answer

The normalized vector is

v/|v|

where |v|=sqrt(u_x^2+u_y^2+u_z^2)

hence |v|=sqrt(0^2+4^2+4^2) or |v|=4*sqrt2

Hence

v/|v|=(0/(4*sqrt2) , 4/[4*sqrt2],4/[4*sqrt2])

v/|v|=(0,1/sqrt2,1/sqrt2)