How do you normalize <0, 1, 3>?

1 Answer
Aug 7, 2017

hatv = < 0, 1/(sqrt10), 3/(sqrt10) >

Explanation:

Normalization of a vector is the process of finding a unit vector in the same direction of that vector (with magnitude (or "norm") 1). It is found by the equation

ulbar(|stackrel(" ")(" "hatv = (vecv)/(||vecv||)" ")|)

where

hatv denotes the unit vector

||vecv|| is the magnitude of vector vecv

The magnitude of vecv is given by

||vecv|| = sqrt(0^2 + 1^2 + 3^2) = color(red)(ul(sqrt10

Thus, we have

hatv = (< 0,1,3 >)/(color(red)(sqrt10)) = color(blue)(ulbar(|stackrel(" ")(" "< 0, 1/(sqrt10), 3/(sqrt10) >" ")|)