How do you multiply #(5+2sqrt6)(2+sqrt6)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Alan P. Apr 7, 2015 In general #(a+b)*(c+d) = (a+b)c + (a+b)d# So we can re-write #(5+2sqrt(6))(2+sqrt(6))# as #(5+2sqrt(6))(2) + (5+sqrt(6))(sqrt(6))# #= (10 + 4sqrt(6)) + (5sqrt(6) + 6)# #= 16 + 9sqrt(6)# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1290 views around the world You can reuse this answer Creative Commons License