How do you multiply #(2n+2)(6n+1)#?

1 Answer
Alan P.
Jul 8, 2015

One method is through multiple application of the distribution property.
#(2n+2)(6n+1) = 12n^2+14n+2#

Explanation:

#(2n+2)(6n+1)#
#color(white)("XXXX")##= 2n(6n+1) + 2(6n+1)#

#color(white)("XXXX")##=(12n^2+2n)+(12n+2)#

#color(white)("XXXX")##= 12n^2 +(2n+12n) + 2#

#color(white)("XXXX")##=12n^2+14n +2#

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