How do you long divide #(x^2 + 6x +5)/(x^2-3x-4)#? Precalculus Real Zeros of Polynomials Long Division of Polynomials 1 Answer Adrian D. Sep 8, 2015 #(x+5)/(x-4)# Explanation: By factoring we have: #(x^2+6x+5)/(x^2-3x-4)=(cancel((x+1))(x+5))/(cancel((x+1))(x-4))# Answer link Related questions What is long division of polynomials? How do I find a quotient using long division of polynomials? What are some examples of long division with polynomials? How do I divide polynomials by using long division? How do I use long division to simplify #(2x^3+4x^2-5)/(x+3)#? How do I use long division to simplify #(x^3-4x^2+2x+5)/(x-2)#? How do I use long division to simplify #(2x^3-4x+7x^2+7)/(x^2+2x-1)#? How do I use long division to simplify #(4x^3-2x^2-3)/(2x^2-1)#? How do I use long division to simplify #(3x^3+4x+11)/(x^2-3x+2)#? How do I use long division to simplify #(12x^3-11x^2+9x+18)/(4x+3)#? See all questions in Long Division of Polynomials Impact of this question 1956 views around the world You can reuse this answer Creative Commons License