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How do you integrate #x5^(x^2) dx#?

1 Answer

Sep 3, 2016

#1/(2log_e5)5^(x^2)+C#

Explanation:

#d/(dx)(5^(x^2)) = 2 x log_e5 xx 5^(x^2)# then

#int x5^(x^2) dx = 1/(2log_e5)int d/(dx)(5^(x^2)) = 1/(2log_e5)5^(x^2)+C#

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