How do you integrate #x^-1#? Calculus Introduction to Integration Integrals of Polynomial functions 1 Answer Ratnaker Mehta Sep 8, 2016 #intx^-1dx=int1/xdx=ln|x|+C#. The Standard Form #int x^ndx=x^(n+1)/(n+1)# is not applicable here, as for #n=-1, (n+1)=0;" &, we can't divide by "#0#. Answer link Related questions How do you evaluate the integral #intx^3+4x^2+5 dx#? How do you evaluate the integral #int(1+x)^2 dx#? How do you evaluate the integral #int8x+3 dx#? How do you evaluate the integral #intx^10-6x^5+2x^3 dx#? What is the integral of a constant? What is the antiderivative of the distance function? What is the integral of #|x|#? What is the integral of #3x#? What is the integral of #4x^3#? What is the integral of #sqrt(1-x^2)#? See all questions in Integrals of Polynomial functions Impact of this question 1415 views around the world You can reuse this answer Creative Commons License