How do you integrate sec^3x (tanx) dx?
1 Answer
Oct 4, 2016
Explanation:
When working with integrals of secant and tangent, it's important to remember the following:
d/dxtanx=sec^2x d/dxsecx=secxtanx
Here, we see that we can write
intsec^3x(tanx)dx=intsec^2x(secxtanx)dx
With
=intu^2du=u^3/3+C=sec^3x/3+C