How do you integrate $int x/(x-6) dx$ using partial fractions?

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Answer 1 · 2015-11-08T02:01:35

Don't need to use partial fractions.

Step 1: divide $(x-6)$ into $x$ using long division:

$x/(x-6)=1+6/(x-6)$

Step 2: Integrate

$int[1+6/(x-6)]dx=x+6ln(x-6)+C$

hope that helped

How do you integrate int x/(x-6) dxint x/(x-6) dx using partial fractions?