How do you integrate #int root4(x^3)+1dx#? Calculus Introduction to Integration Integrals of Polynomial functions 1 Answer A. S. Adikesavan Nov 13, 2016 #3/7 x^(7/3)+x+C# Explanation: This is #int( (x^3)^(1/4)+1) dx# #=x^(7/3)/(7/3)+x+C# #=3/7 x^(7/3)+x+C# Answer link Related questions How do you evaluate the integral #intx^3+4x^2+5 dx#? How do you evaluate the integral #int(1+x)^2 dx#? How do you evaluate the integral #int8x+3 dx#? How do you evaluate the integral #intx^10-6x^5+2x^3 dx#? What is the integral of a constant? What is the antiderivative of the distance function? What is the integral of #|x|#? What is the integral of #3x#? What is the integral of #4x^3#? What is the integral of #sqrt(1-x^2)#? See all questions in Integrals of Polynomial functions Impact of this question 1460 views around the world You can reuse this answer Creative Commons License