How do you integrate #int (root3x)#? Calculus Introduction to Integration Integrals of Polynomial functions 1 Answer Andrea S. Feb 21, 2017 #int root(3)x dx = 3/4 xroot(3)x +C# Explanation: You can integrate using the power rule: #int x^alpha dx = x^(alpha+1)/(alpha+1) + C# In our case: #int root(3)x dx = int x^(1/3)dx = x^(4/3)/(4/3) + C = 3/4 xroot(3)x +C# Answer link Related questions How do you evaluate the integral #intx^3+4x^2+5 dx#? How do you evaluate the integral #int(1+x)^2 dx#? How do you evaluate the integral #int8x+3 dx#? How do you evaluate the integral #intx^10-6x^5+2x^3 dx#? What is the integral of a constant? What is the antiderivative of the distance function? What is the integral of #|x|#? What is the integral of #3x#? What is the integral of #4x^3#? What is the integral of #sqrt(1-x^2)#? See all questions in Integrals of Polynomial functions Impact of this question 2115 views around the world You can reuse this answer Creative Commons License