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How do you integrate #int pisinpix dx#?

1 Answer

Dec 6, 2016

Using #u#-substitution, we will find a value in the function whose derivative will appear in the integrand.

Thus, we will let:

#u=pix#
#du=pidx#

So, if we plug it back in:

#=intsin(u)du#

#=-cos(u)+c#

#=-cos(pix)+c#

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