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How do you integrate $int e^(-2x)dx$ from $[0,1]$ ?

1 Answer

Nov 28, 2016

In general $int(e^(alphax))dx = 1/alphae^(alphax)$

Explanation:

$int_0^1e^(-2x)dx = -1/2e^(-2x)|_0^1=-1/2 (e^-2-1)$

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