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How do you integrate #int csc^2(x/2) dx#?

1 Answer

Dec 14, 2016

#" "intcsc^2(x/2)dx=-2cot(x/2)+C#

Explanation:

#d/(dx)(cotx)=-csc^2x#

so#" "d/(dx)(cot(x/2))=-1/2csc^2x#

inspecting #" "intcsc^2(x/2)dx#

we have to adjust for the #" "-1/2#

#" "intcsc^2(x/2)dx=-2cot(x/2)+C#

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